Physics for girls

physics for girls

 

← Back to Atomic Structure contents

ATOMIC STRUCTURE · CHAPTER 12 OF 12

What powers the stars?

The Sun releases energy without burning fuel in oxygen. Deep in its core, light nuclei join. Why is this possible inside a star—and so difficult to use in a power station on Earth?

By the end, you’ll be able to…

  • describe fusion as light nuclei joining to form a heavier nucleus
  • explain energy release using a decrease in total rest mass
  • explain the conditions needed for fusion and how they occur inside stars
  • compare fusion with fission
  • explain the scientific and engineering challenges of fusion electricity generation.

Fusion joins light nuclei

Nuclear fusion joins two light nuclei to form a heavier nucleus. Suitable reactions release energy because the products have less total rest mass than the reacting nuclei.

One important example for fusion research uses two hydrogen isotopes: deuterium, with one proton and one neutron, and tritium, with one proton and two neutrons. They can form a helium-4 nucleus and a neutron.

This deuterium–tritium reaction is a useful example for studying fusion, but it is not the main reaction sequence powering the Sun.

INTERACTIVE FUSION MODEL

Where do the five nucleons go?

Follow the three stages. Count protons and neutrons before and after. The outgoing neutron is part of the products, not a missing particle.

++Deuterium · 2 nucleonsTritium · 3 nucleons
Total before: 2 protons + 3 neutrons = 5 nucleons. Each starting nucleus has positive charge, so they repel electrostatically.
++Positive nuclei must approach very closely
High-energy encounters can bring nuclei close enough for the attractive strong nuclear interaction to bind them. This is a simplified model of how fusion can occur.
++Helium-4 · 4 nucleons1 neutronKinetic energy is carried by the products
Total after: helium has 2 protons and 2 neutrons, plus 1 separate neutron. There are still 5 nucleons, but the products have less total rest mass and carry the released energy.
+ Proton Neutron− Electron

* Compact particle diagrams, not to scale. Faint circles show approximate nuclear extent, not walls. Electrons are omitted. Animated repeats represent separate reactions. The model does not show every intermediate step.

Check what is conserved

+→+

Nucleon number

2 + 3 = 4 + 1
5 = 5

Charge

1 + 1 = 2 + 0
2 = 2

The mass numbers balance. That is different from saying the total rest mass in kilograms is exactly unchanged.

Do not leave out the neutron when comparing the products’ total mass with the reactants’ total mass. Compare deuterium + tritium with helium + neutron, not with helium alone.

Why does fusion release energy?

When light nuclei fuse, the resulting particles can form a more tightly bound arrangement. Their combined rest mass is slightly lower than that of the starting nuclei.

The difference in rest mass corresponds to energy released, mainly as kinetic energy of the helium nucleus and neutron.

No protons or neutrons disappear. Total energy is conserved.

▶ INTERACTIVE

Why does fusion release energy?

Select After fusion to see how the combined rest mass changes when deuterium and tritium fuse.

BEFORE AFTER + Deuterium + tritium Helium + neutron Energy released Higher rest mass Lower rest mass
Proton Neutron
Before fusion: Deuterium and tritium contain two protons and three neutrons altogether. Their combined rest mass is slightly higher than that of the products.
After fusion: A helium-4 nucleus and a neutron are produced. Their combined rest mass is slightly lower because the final nuclear arrangement is more tightly bound. The difference in rest energy is released mainly as kinetic energy of the products.

* The scales are an analogy, and the mass difference is greatly exaggerated. No protons or neutrons disappear. The orange lightning represents released energy, mainly kinetic energy of the helium nucleus and neutron, rather than a separate burst of radiation.

Why don’t nuclei fuse easily at room temperature?

Both nuclei are positively charged, so electrostatic repulsion tends to push them apart. They must get extremely close for the strong nuclear interaction to bind them.

High temperature means particles have greater average kinetic energy, increasing the chance of sufficiently energetic encounters. High density makes encounters more frequent. The particles must also remain together for long enough: confinement time matters.

High pressure can help produce high density. The useful conditions are a combination of temperature, density and confinement—not simply “squeeze harder” or “make it hot”.

conditions needed for nuclear fusion:
INTERACTIVE FUSION-CONDITIONS EXPLORER

Temperature alone is not the whole story

Compare the three situations. The particle movements illustrate encounter conditions, not a measured fusion rate.

++Repulsion prevents a close enough approach
At low temperature, there are too few sufficiently energetic close encounters for a useful fusion rate. The nuclei repel before coming close enough.
+++−−−Fast particles can still have too few encounters
A high temperature raises particle energies, but if fuel is too sparse or escapes too quickly, too few useful collisions occur.
+++++++−−−Maintain enough energetic encounters for useful fusion
A practical system must combine suitable temperature, density and confinement time. Even then, not every collision produces fusion.

* Whole pink + symbols represent positive nuclei in plasma, not separate free protons in every case. Blue − symbols represent electrons. Particle numbers and spacing are schematic; the box is not a literal container suitable for touching hot plasma.

The Sun: gravity makes the conditions possible

The Sun is mostly hydrogen and helium. Its gravity compresses its interior, producing very high pressure and density. The core temperature is about 15 million °C. The Sun’s enormous mass provides gravitational confinement, allowing fusion to continue in its core over billions of years.

In the core, a sequence of nuclear reactions converts hydrogen into helium and releases energy. Hydrogen fusion powers the Sun and many other stars; other fusion processes occur in stars at different stages.

The Sun is not a chemical fire and does not need a supply of oxygen for fusion. Its main hydrogen-fusion sequence is different from the deuterium–tritium example used above.

INTERACTIVE STAR EXPLORER

Look inside the Sun

Select a feature to see how fusion, gravity and energy transfer are connected inside the Sun.

+ + + + + + About 15 million °C Fusion in the core Hydrogen nuclei → helium nucleus + energy Simplified overall result Core Gravity acts inwards Core Energy outwards Energy is eventually emitted into space
Fusion in the core: The Sun's core is about 15 million °C. Hydrogen nuclei undergo a series of fusion reactions that ultimately produce helium. During this process, two protons are converted into neutrons, and energy is released. The animation shows the simplified overall result, not one direct collision.
Gravity and pressure: Gravity compresses the Sun's interior. In a stable star, the inward pull of gravity is balanced by an outward pressure gradient. Fusion helps maintain the hot interior.
Energy reaches space: Energy released in the core is transferred through the Sun's interior and eventually emitted from its surface as electromagnetic radiation.

* Colours represent relative temperatures, not the Sun's actual colours. Pink particles represent protons; white particles represent neutrons. The gravity arrows show the direction of gravitational pull, not the Sun shrinking.

Fusion on Earth needs confinement

We cannot reproduce a star’s enormous gravitational confinement in a power station. One approach heats an ionised gas—a plasma—and uses magnetic fields to guide and confine its charged particles.

A tokamak holds plasma in a ring-shaped region. The plasma must be kept sufficiently hot while limiting contact with material walls, where it would lose energy. Magnets influence charged particles; they do not directly confine uncharged fusion neutrons.

Another approach uses powerful laser pulses to compress and heat a small fuel target for a very short time. Both approaches must achieve suitable temperature, density and confinement.

INTERACTIVE FUSION-MACHINE MODEL

What do the magnets actually confine?

Compare charged plasma particles with an uncharged fusion neutron. This is a schematic ring view, not the detailed field geometry.

+−Magnetic confinement · schematic tokamak
Magnetic fields guide charged nuclei and electrons, helping keep the hot plasma away from the walls. Real particle trajectories spiral along complex field lines; the drawn loops only illustrate confinement.
+−NeutronMagnetic confinement · schematic tokamak
In deuterium–tritium fusion, a neutron carries much of the released energy. It is uncharged and is not directly confined by the magnetic field. Interactions in surrounding material transfer its energy to that material.
+−NeutronMagnetic confinement · schematic tokamak
A proposed power system would collect the released energy, transfer it to a coolant and generate electricity through a thermal cycle. Heating, magnets, cooling, pumps and other equipment also require energy.

* Plasma shading is not a positive electrical charge filling the machine. Pink + particles are nuclei; blue − particles are electrons; white particles are neutrons. The wall, magnets and particle paths are not to scale.

Why is a practical power station difficult?

Maintain the conditionsHeat and confine enough fuel for long enough while limiting energy losses and plasma instabilities.
Protect the machineManage intense heat and neutron bombardment, maintain materials and handle radioactive tritium safely.
Supply useful outputConvert released energy to electricity while covering the energy needs of the entire facility reliably and economically.

Producing fusion reactions is not the same as supplying net electricity to a grid. An experimental energy gain may compare fusion output with energy delivered to the fuel, while a power station must account for all its electrical inputs and conversion losses.

Deuterium is available in water, but tritium is radioactive and scarce. Deuterium–tritium systems must address fuel supply, potential neutron activation of materials and radioactive-material management. Fusion is not accurately described as “no radioactivity anywhere”.

Fusion does not require the same neutron-driven fission chain as a uranium reactor. If fusion conditions are lost, the fusion rate falls. That does not remove engineering hazards, stored energy or the need to manage radioactive materials.

Fission and fusion: compare the nuclear changes

FeatureFissionFusion
Starting nucleiA suitable heavy nucleus, such as U-235Suitable light nuclei, such as hydrogen isotopes
Main changeA nucleus splits into smaller nucleiNuclei join to form a heavier nucleus
Energy releaseProducts have lower total rest massProducts have lower total rest mass in an energy-releasing reaction
Key conditionsNeutron availability and reactor controlSuitable temperature, density and confinement
NeutronsCan continue a fission chainCan be products, as in D–T fusion; this is not the same fission chain
INTERACTIVE SORT THE PROCESS

Which process is described?

Two light nuclei form a more tightly bound product system, releasing energy. Which process is this?
Correct. Light nuclei join; the released energy corresponds to a lower total rest mass of the products.
Try again. Fission splits a suitable heavy nucleus.
Try again. Ionisation removes an electron from an atom; it does not join nuclei.

Three worked examples

Use the supplied values. You do not need to memorise an energy per fusion reaction or calculate a mass defect for these questions.

Relate reaction number, energy and power:

Calculate energy released:

Given 2.8 × 10⁻¹² J per reaction, find the release from 5.0 × 10¹² reactions.

E = number of reactions × energy per reaction

E = (5.0 × 10¹²) × (2.8 × 10⁻¹²)

E = 14 J

Calculate power:

A hypothetical system releases 1.8 × 10⁹ J in 6 s.

P = E ÷ t

P = 1.8 × 10⁹ ÷ 6

P = 3.0 × 10⁸ W = 300 MW

Calculate conversion efficiency:

A hypothetical thermal system receives 500 MW and supplies 200 MW electrically.

Efficiency = useful output ÷ input × 100%

Efficiency = 200 ÷ 500 × 100%

Efficiency = 40%

INTERACTIVE WHOLE-SYSTEM ENERGY CHECK

Does output automatically mean net supply?

A hypothetical plant produces 200 MW of electricity. Its own equipment uses 150 MW. Compare gross output with net export.

200 MW gross
The generator’s gross electrical output is 200 MW. This value does not yet subtract the plant’s own electricity use.
150 MW internal demand
Heating, confinement equipment, coolant pumps and other systems together use 150 MW in this supplied example.
50 MW net export
Net export = 200 − 150 = 50 MW. A practical system must sustain useful net output, not merely release energy in the fuel.

INTERACTIVE QUICK CHECK

Check your understanding

Choose one answer for each question. Feedback appears underneath.

1. What powers the Sun’s main hydrogen-burning stage?
Try again. The Sun’s principal energy source is nuclear, not ordinary chemical combustion.
Correct. Hydrogen-fusion reactions in the core release energy.
Try again. The Sun is not powered by a surface uranium-fission reactor.
2. Why are high temperatures important for useful fusion rates?
Correct. Positive nuclei repel; sufficiently energetic encounters are more likely to bring them close enough to fuse.
Try again. Removing electrons creates plasma, but nuclei retain their positive charge.
Try again. Neutrons remain uncharged.
3. Which statement about D–T fusion is correct?
Try again. Deuterium plus tritium gives five nucleons: four in helium and one neutron.
Try again. Nucleon number is not the same as an exact rest-mass measurement.
Correct. Nucleon number and charge balance, while energy is released.
INTERACTIVE CHALLENGE

“Fusion joins nuclei, so it should happen whenever hydrogen is squeezed together. A fusion energy gain of more than one proves a power station can export electricity.” Explain the errors.

Use electrostatic repulsion, temperature, density, confinement and the boundary used for an energy comparison.

Reveal the answer

Positive nuclei repel. Squeezing increases density, but a useful fusion rate also needs sufficiently energetic close encounters and appropriate confinement time. High temperature, density and confinement must work together.

A reported gain depends on which input is counted—for example energy delivered to the fuel. A power station must also cover heating-system losses, magnets, cooling, pumps and other facility demands, and convert released energy into electricity.

Useful net electrical export therefore requires a whole-system comparison. A positive result using a narrower experimental boundary does not by itself establish a practical or economic power station.

CHAPTER 12

Chapter summary

  • Fusion joins light nuclei to form a heavier nucleus.
  • D–T fusion produces helium-4 and a neutron, with five nucleons conserved.
  • An energy-releasing fusion reaction has lower total product rest mass; the difference corresponds to released energy.
  • Positive nuclei repel. High temperature, suitable density and confinement enable useful fusion rates.
  • The Sun’s core supports hydrogen-fusion reactions; its main sequence is not the D–T example.
  • Magnetic confinement acts on charged plasma particles, not uncharged neutrons.
  • A fusion power system must manage energy losses, materials, fuel and whole-facility demand.
  • Fission splits heavy nuclei; fusion joins light nuclei. Both can release nuclear energy.